Most chemical reactions don't go to completion. They reach a state where reactants and products coexist. That state is equilibrium. Unit 7 is about understanding how and why reactions reach equilibrium, what it means for the reaction to be at equilibrium, and how to calculate and predict equilibrium concentrations. You'll work with the equilibrium constant, Le Châtelier's principle, and solubility equilibria.
🎯 What You Need to Know for the Exam
Unit 7 makes up about 7-9% of the AP Chemistry exam. Focus your energy on these priorities:
What's in this review:
Topic 7.1: Introduction to Equilibrium
Most chemical and physical processes are reversible. Water evaporates and condenses. Gases dissolve in and escape from solutions. Salts dissolve in water and then precipitate out. In all these cases, both the forward and reverse processes are happening at the same time.
When a reversible reaction first begins, the forward reaction dominates and products form. But as products accumulate, the reverse reaction starts to pick up speed. Eventually, the forward and reverse reactions proceed at the same rate. When this happens, the concentrations of all reactants and products stay constant. This is equilibrium. The key insight is that equilibrium is dynamic. The reactions don't stop. Both directions continue, but they balance each other out.
You can see equilibrium being established by plotting concentration or pressure versus time. At first, reactant concentration drops and product concentration rises. Then both curves flatten out and stay constant. That flat region is equilibrium. Graphs of reaction rate versus time show both forward and reverse rates. At equilibrium, these lines meet.
Key concepts to know:
⚠ Watch out for:
Students often think that at equilibrium, the reaction has stopped. It hasn't. Both forward and reverse reactions continue at equal rates. Also, "equilibrium" doesn't mean equal concentrations of reactants and products. It means equal rates of reaction in both directions.
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Topic
AP Chemistry: Equilibrium Fundamentals
Focus on
Reversible reactions, dynamic equilibrium, rate equality at equilibrium
📝 Quiz · 15 questions
Topic
AP Chemistry: Equilibrium Fundamentals
Description
Identify equilibrium states, explain dynamic equilibrium, interpret concentration-time graphs
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The direction a reaction proceeds depends on comparing the rates of the forward and reverse reactions. If the forward reaction is faster, reactants convert to products and the reaction moves right. If the reverse reaction is faster, products convert back to reactants and the reaction moves left. Equilibrium occurs when these rates are equal.
This is simpler than it sounds. You don't need to calculate the actual rates. You just need to know how to compare them using the reaction quotient (Q) and the equilibrium constant (K). For now, focus on the principle: whichever direction has the faster rate is the direction the reaction will proceed.
Key concepts to know:
⚠ Watch out for:
Don't confuse "equal rates" with "equal concentrations." At equilibrium, forward and reverse rates are equal, but that doesn't mean [reactants] = [products]. The equilibrium concentrations depend on the equilibrium constant, not on equal amounts.
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Topic
AP Chemistry: Reaction Rates and Direction
Focus on
Forward vs. reverse rates, predicting reaction direction, rate equality
📝 Quiz · 10 questions
Topic
AP Chemistry: Reaction Rates and Direction
Description
Determine which direction a reaction will shift based on comparing forward and reverse rates
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The reaction quotient (Q) and the equilibrium constant (K) are expressions that describe the ratio of products to reactants in a reaction. They have the same mathematical form. For a generic reaction aA + bB ⇌ cC + dD, the equilibrium expression is:
K = [C]^c [D]^d / [A]^a [B]^b
The equilibrium constant K uses equilibrium concentrations. The reaction quotient Q uses whatever concentrations are present at any moment in the reaction. The Q expression is identical to the K expression, but Q changes as the reaction proceeds. K is a constant for a given reaction at a given temperature.
An important detail: the expression doesn't include pure solids or pure liquids. If you have a solid reactant or product, you leave it out of the Q and K expressions. The concentration of a solid doesn't change as it dissolves or precipitates, so it doesn't appear.
Key concepts to know:
⚠ Watch out for:
Remember the stoichiometric coefficients. If the equation is N2 + 3H2 ⇌ 2NH3, then K = [NH3]^2 / ([N2][H2]^3). The exponents come from the coefficients, not from the subscripts in the formula. Also, don't forget to omit solids and pure liquids from your expression. Note: conversion between Kc and Kp (using Kp = Kc(RT)^Δn) is excluded from the AP Exam. You should know that both forms exist and when each is used, but you won't be asked to convert between them.
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Topic
AP Chemistry: Equilibrium and Reaction Quotient Expressions
Focus on
Writing Q and K expressions, stoichiometric coefficients, exclusion of solids and liquids
📝 Quiz · 15 questions
Topic
AP Chemistry: Equilibrium and Reaction Quotient Expressions
Description
Write and calculate Q and K expressions, identify which substances to include
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You calculate the equilibrium constant by measuring the concentrations (or partial pressures) of all species when the system reaches equilibrium, and then plugging those values into the equilibrium expression.
Here's the process: (1) Start with the balanced equation. (2) Write the equilibrium expression. (3) Measure or determine the equilibrium concentrations. (4) Substitute into the expression and calculate K.
The equilibrium constant is always the same for a given reaction at a given temperature, regardless of initial concentrations. Whether you start with pure reactants or a mixture of reactants and products, the equilibrium constant stays the same. This makes K a useful tool for predicting where the system will end up.
Key concepts to know:
⚠ Watch out for:
Make sure you're using equilibrium concentrations, not initial concentrations. If the problem gives you initial conditions and some changes, you need to calculate the equilibrium concentrations first using an ICE table, then plug those into K.
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Topic
AP Chemistry: Calculating K from Experimental Data
Focus on
Finding equilibrium concentrations, substituting into equilibrium expressions, solving for K
📝 Quiz · 10 questions
Topic
AP Chemistry: Calculating K from Experimental Data
Description
Calculate K from given equilibrium data, interpret results
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The size of K tells you something crucial about the reaction. A very large K (like 10^6 or larger) means the reaction goes essentially to completion. Nearly all reactants convert to products, and at equilibrium, products dominate. A very small K (like 10^-6 or smaller) means the reaction barely proceeds at all. The system remains mostly reactants, with only a tiny amount of products formed.
If K is around 1, then reactants and products are present in similar amounts at equilibrium. For intermediate values of K, the position of equilibrium is somewhere between mostly reactants and mostly products.
This is a key conceptual insight: K tells you the direction the reaction favors. Large K favors products. Small K favors reactants. You don't need to do calculations to know the outcome. Just look at the magnitude of K.
Key concepts to know:
⚠ Watch out for:
Don't confuse a large K with a reaction that happens quickly. K tells you where equilibrium is, not how fast you get there. A reaction with K = 10^10 might reach equilibrium in seconds or take years. Speed and position are separate concepts.
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Topic
AP Chemistry: Interpreting K Values
Focus on
Large K vs. small K, predicting which direction is favored, K and completion
📝 Quiz · 10 questions
Topic
AP Chemistry: Interpreting K Values
Description
Interpret K magnitudes, predict equilibrium outcomes
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The equilibrium constant has algebraic properties that make it powerful. When you reverse a reaction, K becomes its reciprocal (1/K). If K for the forward reaction is 100, then K for the reverse reaction is 1/100 = 0.01. When you multiply the coefficients of a reaction by a factor, you raise K to that same power. If you double the coefficients, you square K. If you divide by 2, you take the square root of K.
When you add two reactions together, you multiply their K values. This is why K is useful: it lets you combine reactions algebraically and find the K for the overall reaction.
These properties follow directly from the mathematical form of the equilibrium expression. They're not arbitrary. Understanding them helps you manipulate equilibrium problems efficiently.
Key concepts to know:
⚠ Watch out for:
Be careful when multiplying reactions. If you reverse one and keep the other forward, you reverse the K of one reaction and multiply. For example, if Reaction 1: K1 = 10 and Reaction 2 (reversed): 1/K2 = 0.5, then the overall K = (1/10) × (0.5) = 0.05. Track which reactions you're reversing.
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Topic
AP Chemistry: Equilibrium Constant Algebra
Focus on
Reversing reactions, multiplying coefficients, combining reactions
📝 Quiz · 15 questions
Topic
AP Chemistry: Equilibrium Constant Algebra
Description
Calculate K for overall reactions, reverse and multiply reactions
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This is where the equilibrium constant becomes a practical tool. You're given initial concentrations and K, and you need to find the equilibrium concentrations. The standard method is an ICE table: Initial, Change, Equilibrium.
Start by writing the balanced equation and the equilibrium expression. Fill in the initial concentrations. Use stoichiometry to determine how the concentrations change as the reaction proceeds. If you know that concentration of A drops by x, then concentrations of B and C change by -x or +x depending on stoichiometry. Finally, calculate the equilibrium concentrations and use them to solve for any unknown.
The key comparison is Q versus K. If Q < K, the reaction will shift right (forward) to make more products. If Q > K, the reaction will shift left (reverse) to make more reactants. If Q = K, the system is at equilibrium and no shift occurs.
Key concepts to know:
⚠ Watch out for:
Track signs carefully. If a reactant decreases, its change is negative. If a product increases, its change is positive. Use the stoichiometry to make sure the changes are proportional to the coefficients. The most common mistake is getting the stoichiometric relationships wrong in the ICE table.
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Topic
AP Chemistry: ICE Tables and Equilibrium Calculations
Focus on
ICE tables, stoichiometric changes, solving for equilibrium concentrations
📝 Quiz · 20 questions
Topic
AP Chemistry: ICE Tables and Equilibrium Calculations
Description
Build ICE tables, calculate unknown concentrations using K
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You can describe an equilibrium system using words, equations, or particulate diagrams. A particulate representation shows reactant and product particles before and at equilibrium. The relative numbers of each type of particle give you a visual sense of the equilibrium position.
For example, if you have a container with N2O4 ⇌ 2NO2, a particulate diagram before equilibrium might show many N2O4 molecules and few NO2 molecules. At equilibrium, the diagram shows fewer N2O4 molecules and more NO2 molecules, depending on K.
These diagrams help you see that equilibrium is about the relative amounts present, not absolute numbers. A large K means more product particles relative to reactant particles at equilibrium. A small K means mostly reactant particles.
Key concepts to know:
⚠ Watch out for:
When interpreting particulate diagrams, count carefully. The diagram shows relative particle numbers, and you can use these to calculate K by determining the concentrations represented by the particle counts.
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Topic
AP Chemistry: Particulate Models of Equilibrium
Focus on
Interpreting particle diagrams, calculating K from particle counts
📝 Quiz · 10 questions
Topic
AP Chemistry: Particulate Models of Equilibrium
Description
Interpret equilibrium diagrams, relate particle counts to K values
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Le Châtelier's principle says that when a system at equilibrium is disturbed, it will shift to counteract the disturbance. If you add a reactant, the system will consume some of it by shifting right. If you remove a product, the system will produce more by shifting right. If you increase temperature, the system will respond based on whether the reaction is exothermic or endothermic.
The stresses you can apply are: adding or removing species, changing temperature, changing volume or pressure (for gas systems), or diluting the solution. The system responds by shifting left or right to minimize the effect of the stress. It never fully cancels the stress, but it reduces it.
This principle is powerful because it lets you predict what will happen without calculations. You just need to think about which direction the system will shift to reduce the stress.
Key concepts to know:
⚠ Watch out for:
Le Châtelier's principle tells you which way a system shifts, but it doesn't tell you by how much or how fast. It also doesn't completely cancel the stress. If you add a reactant, some of it will be consumed, but the concentration of that reactant is still higher than before you added it.
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Topic
AP Chemistry: Le Châtelier's Principle
Focus on
Predicting shifts, identifying stresses, applying Le Châtelier's principle
📝 Quiz · 15 questions
Topic
AP Chemistry: Le Châtelier's Principle
Description
Predict system responses to stresses, interpret observable changes
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When you disturb an equilibrium system, Q changes. If the disturbance adds reactants or removes products, Q decreases and becomes less than K. The system shifts right (forward) to bring Q back to K. If the disturbance removes reactants or adds products, Q increases and becomes greater than K. The system shifts left (reverse) to bring Q back down to K.
Temperature is special. Changing temperature actually changes K. For an exothermic reaction, increasing temperature makes K smaller. For an endothermic reaction, increasing temperature makes K larger. The system responds by shifting to establish a new equilibrium with the new K value.
This is the mechanism behind Le Châtelier's principle. The system always tries to return to Q = K. If you change K (by changing temperature), the system shifts until Q again equals the new K.
Key concepts to know:
⚠ Watch out for:
Remember that concentration changes don't affect K, only Q. Temperature changes affect K. This is a critical distinction. A concentration change causes a shift to a new equilibrium with the same K. A temperature change shifts to a new equilibrium with a different K.
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Topic
AP Chemistry: Q and K Relationships
Focus on
Q vs. K, predicting shifts, temperature effects on K
📝 Quiz · 15 questions
Topic
AP Chemistry: Q and K Relationships
Description
Apply Q vs. K to predict shifts and interpret equilibrium changes
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When a salt dissolves in water, the dissolution process is reversible. The solid dissolves to form ions in solution, and ions precipitate back out to reform the solid. At equilibrium, both processes are happening at equal rates. The system reaches solubility equilibrium.
The solubility product constant (Ksp) is the equilibrium constant for this dissolution process. For a salt like AgCl, the dissolution is AgCl(s) ⇌ Ag+(aq) + Cl-(aq), and Ksp = [Ag+][Cl-]. The Ksp is always written with products (ions in solution) in the numerator and excludes the solid.
Ksp tells you how soluble a salt is. A large Ksp means the salt is very soluble (lots of ions in solution at equilibrium). A small Ksp means the salt is barely soluble (few ions in solution at equilibrium). You can calculate the molar solubility of a salt using Ksp. You can also use Ksp to predict whether a precipitate will form when two solutions are mixed.
Key concepts to know:
⚠ Watch out for:
Remember that Ksp only describes the equilibrium between the solid and the saturated solution. It doesn't tell you anything about the dissolution rate or how long it takes to reach equilibrium. Also, be careful with the exponents in the Ksp expression. They come from the stoichiometry of the dissolution, not from the subscripts in the formula.
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Topic
AP Chemistry: Solubility Equilibria and Ksp
Focus on
Writing Ksp expressions, calculating solubility from Ksp, predicting precipitation
📝 Quiz · 15 questions
Topic
AP Chemistry: Solubility Equilibria and Ksp
Description
Calculate Ksp and solubility, determine if a precipitate will form
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The common-ion effect describes what happens when you add an ion that's already present in a solubility equilibrium. For example, if you have a saturated solution of AgCl, adding more Cl- ions will cause some AgCl to precipitate out and the solubility of AgCl to decrease.
This is an application of Le Châtelier's principle to solubility equilibria. When you increase the concentration of one of the ions (the common ion), Q temporarily exceeds Ksp, so the system shifts left and more precipitate forms. The solubility decreases because some of the salt must precipitate to restore the Ksp equilibrium.
You can calculate the effect using Le Châtelier's principle qualitatively, or you can set up an equilibrium expression with the new ion concentration and calculate the new solubility quantitatively.
Key concepts to know:
⚠ Watch out for:
The common-ion effect only decreases solubility. It doesn't increase it. If you add a non-common ion (an ion not present in the dissolution equilibrium), it might change solubility, but that's a different effect and usually small. Focus on the common-ion effect as shown in the CED.
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Topic
AP Chemistry: Common-Ion Effect
Focus on
How adding a common ion affects solubility, predicting precipitation, Le Châtelier's principle
📝 Quiz · 10 questions
Topic
AP Chemistry: Common-Ion Effect
Description
Apply common-ion effect to solubility problems, calculate new solubility values
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Unit 7 is mathematical and conceptual. Here are strategies that work:
Master ICE tables. Equilibrium calculations depend on them. Practice until you can set up an ICE table in your sleep. Get the stoichiometry right. Check your work by substituting back into the equilibrium expression.
Understand Q versus K. This is the heartbeat of equilibrium chemistry. Q tells you which direction the reaction will shift. Practice comparing them without calculating exact values.
Practice Le Châtelier with actual systems. Pick real reactions and predict what happens when you change temperature, pressure, or concentration. Use Le Châtelier to check your intuition before doing calculations.
Distinguish concentration changes from temperature changes. Concentration changes shift the system to the same K. Temperature changes shift to a different K. This distinction comes up constantly on the exam.
Use Ksp for precipitation problems. Set up the Ksp expression carefully. Make sure you know whether you're calculating Ksp from solubility, or solubility from Ksp. Both are tested.
StarSpark Practice Prompts:
You've covered all the topics in Unit 7. Before you move on, test yourself with these scenario-based questions. If you can answer them confidently, you're in great shape for this section of the exam.
Review Questions: Test Yourself
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Unit 7 is where equilibrium becomes your central tool for predicting chemical behavior. The equilibrium constant connects everything: it tells you the direction of reactions, the extent of reactions, how systems respond to stress, and how solids dissolve in water.
Check out the full AP Chemistry study plan to see how this unit connects to the rest of the course.
Other Unit Reviews:
For official AP Chemistry resources, visit apcentral.collegeboard.org.
This review is aligned with the AP Chemistry Course and Exam Description. AP is a registered trademark of the College Board, which was not involved in the production of this guide.